2(2-2y)^2-(2-2y)y-6=0

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Solution for 2(2-2y)^2-(2-2y)y-6=0 equation: 



2(2-2y)^2-(2-2y)y-6=0

We add all the numbers together, and all the variables

2(-2y+2)^2-(-2y+2)y-6=0

We multiply parentheses

2y^2+2(-2y+2)^2-2y-6=0

We add all the numbers together, and all the variables

2y^2-2y+2(-2y+2)^2-6=0

We move all terms containing y to the left, all other terms to the right

2y^2-2y+2(-2y+2)^2=6

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